Comments on: What is the tension force and the force applied by the boom? http://pennbradoilmuseum.com/boom/what-is-the-tension-force-and-the-force-applied-by-the-boom Thu, 18 Nov 2010 12:02:59 -0500 http://wordpress.org/?v=2.8.2 hourly 1 By: Technobuff http://pennbradoilmuseum.com/boom/what-is-the-tension-force-and-the-force-applied-by-the-boom/comment-page-1#comment-3924 Technobuff Tue, 24 Nov 2009 22:18:59 +0000 http://pennbradoilmuseum.com/boom/what-is-the-tension-force-and-the-force-applied-by-the-boom#comment-3924 A bit short on info. What it the boom length, does it have weight also, at what position is the 4kg attached? Does the cable attach to the end of the boom? Is force applied by the boom mean the force applied to the wall? You must have had a diagram, or something....<br><b>References : </b><br> A bit short on info.
What it the boom length, does it have weight also, at what position is the 4kg attached?
Does the cable attach to the end of the boom?
Is force applied by the boom mean the force applied to the wall?
You must have had a diagram, or something….
References :

]]> By: kuiperbelt2003 http://pennbradoilmuseum.com/boom/what-is-the-tension-force-and-the-force-applied-by-the-boom/comment-page-1#comment-3923 kuiperbelt2003 Tue, 24 Nov 2009 22:13:59 +0000 http://pennbradoilmuseum.com/boom/what-is-the-tension-force-and-the-force-applied-by-the-boom#comment-3923 does the wall provide any vertical force? If it does, we need to take that into account in solving this problem (we would need to know the length of the sign) If we are not worried about a vertical force from the wall, then we realize that the weight of the sign is supported by the vertical component of tension in the boom. The vertical component of the tension is Tsin30, so we have Tsin30= weight = 4kg x 9.8m/s/s T=39.2N/sin30=78.4N<br><b>References : </b><br> does the wall provide any vertical force? If it does, we need to take that into account in solving this problem (we would need to know the length of the sign)

If we are not worried about a vertical force from the wall, then we realize that the weight of the sign is supported by the vertical component of tension in the boom.

The vertical component of the tension is Tsin30, so we have

Tsin30= weight = 4kg x 9.8m/s/s

T=39.2N/sin30=78.4N
References :

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