A 4.0 kg sign hangs from a boom supported by a cable connected to a wall. The cable makes a 30 degree angle with the boom.
does the wall provide any vertical force? If it does, we need to take that into account in solving this problem (we would need to know the length of the sign)
If we are not worried about a vertical force from the wall, then we realize that the weight of the sign is supported by the vertical component of tension in the boom.
The vertical component of the tension is Tsin30, so we have
Tsin30= weight = 4kg x 9.8m/s/s
T=39.2N/sin30=78.4N
November 24th, 2009 at 5:13 pm
does the wall provide any vertical force? If it does, we need to take that into account in solving this problem (we would need to know the length of the sign)
If we are not worried about a vertical force from the wall, then we realize that the weight of the sign is supported by the vertical component of tension in the boom.
The vertical component of the tension is Tsin30, so we have
Tsin30= weight = 4kg x 9.8m/s/s
T=39.2N/sin30=78.4N
References :
November 24th, 2009 at 5:18 pm
A bit short on info.
What it the boom length, does it have weight also, at what position is the 4kg attached?
Does the cable attach to the end of the boom?
Is force applied by the boom mean the force applied to the wall?
You must have had a diagram, or something….
References :